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Исследование операций и Теория систем 
3. Решим задачу линейного программирования.
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bi
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x1
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x2
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2
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-4
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-6
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6
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-3
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3
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x3
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2
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-1
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2
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1
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-0.5
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0.5
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x4
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2
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1
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1
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-1
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0.5
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-0.5
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x5
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1
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1
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-1
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1
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-0.5
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0.5
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bi
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x1
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x3
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8
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-7
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3
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21/4
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21/4
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-21/8
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x2
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1
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-0.5
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0.5
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3/8
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3/8
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-3/16
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x4
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1
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1.5
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-0.5
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3/4
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3/4
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-3/8
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x5
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2
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0.5
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0.5
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-3/8
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-3/8
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3/16
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bi
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x4
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x3
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53/4
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21/4
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3/8
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x2
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11/8
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3/8
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5/16
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x1
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3/4
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3/4
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-3/8
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x5
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13/8
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-3/8
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11/16
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Оптимальное решение найдено.
Ответ: F=53/4, x1=3/4, x2=11/8, x3=0, x4=0, x5=13/8, x6=0.
Задача 3
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№ вар.
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а1
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а2
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а3
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1
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2
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3
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4
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5
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с11
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с12
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с13
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8
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200
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200
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600
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200
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300
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200
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100
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200
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25
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21
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20
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№ вар.
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с14
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с15
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с21
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с22
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с23
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с24
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с25
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с31
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с32
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с33
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с34
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с35
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8
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50
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18
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15
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30
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32
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25
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40
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23
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40
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10
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12
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21
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Исходные данные:
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B1
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B2
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B3
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B4
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B5
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аi
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A1
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25
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21
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20
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50
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18
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200
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|
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A2
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15
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30
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32
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25
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40
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200
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|
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A3
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23
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40
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10
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12
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21
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600
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bi
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200
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300
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200
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100
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200
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1000
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Определение опорного плана задачи
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B1
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B2
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B3
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B4
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B5
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аi
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|
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A1
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25
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21
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20
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50
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18
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200
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200
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A2
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15
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30
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32
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25
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40
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600
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300
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200
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100
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|
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A3
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23
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40
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10
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12
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21
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200
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200
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bi
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200
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300
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200
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100
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200
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600
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L=5000+9000+6400+2500+4200=27300
r+m-1=7>5 это вырожденный случай.
Определение оптимального плана
1.
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B1
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B2
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B3
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B4
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B5
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аi
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A1
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25
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21
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20
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50
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18
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200+e1
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200
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e1
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A2
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15
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30
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32
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25
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40
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600
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300
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200
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100
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A3
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23
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40
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10
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12
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21
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200+e2
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e2
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200
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bi
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200
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300+e1
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200
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100+e2
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200
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600+e1+e2
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2.
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B1
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B2
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B3
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B4
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B5
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аi
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|
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A1
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25
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21
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20
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50
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18
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200+e1
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0
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200+e1
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A2
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15
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30
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32
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25
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40
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600
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200
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100
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200
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100
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A3
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23
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40
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10
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12
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21
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200+e2
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e2
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200
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bi
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200
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300+e1
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200
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100+e2
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200
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600+e1+e2
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3.
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B1
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B2
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B3
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B4
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B5
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аi
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A1
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25
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21
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20
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50
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18
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200+e1
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0
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200+e1
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A2
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15
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30
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32
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25
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40
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600
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200
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100
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200-e2
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100+e2
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A3
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23
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40
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10
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12
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21
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200+e2
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e2
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200
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bi
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200
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300+e1
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200
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100+e2
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200
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600+e1+e2
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4.
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B1
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B2
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B3
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B4
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B5
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аi
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A1
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25
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21
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20
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50
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18
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200+e1
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0
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e2+e1
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200-e2
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A2
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15
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30
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32
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25
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40
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600
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200
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300-e2
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100+e2
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A3
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23
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40
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10
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12
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21
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200+e2
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e2
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200
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bi
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200
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300+e1
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200
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100+e2
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200
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600+e1+e2
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Страницы: 1, 2, 3, 4
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